mCa(OH)2=40u+32u+2u=74u
%Ca = (40/74)*100% = 54,1%
%O = (32/74)*100% = 43,2%
%H = (2/74)*100% = 2,7%
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mCa(OH)2=40u+32u+2u=74u
%Ca = (40/74)*100% = 54,1%
%O = (32/74)*100% = 43,2%
%H = (2/74)*100% = 2,7%