Question

Oblicz zawartość procentową (procent masowy ) metali w solach
AlCL₃
Pb(NO₃)₂
Na₂SO₄

Answer 1

AlCl3
mAl=27g
mCl= 35,5g
mAlCl3= 27g+3*35,5g=133,5g
27g/133,5g*100%= 20,23%

Pb(NO3)2
mPb(NO3)2= 207g+2*14g+6*16g= 331g
207/331*100%= 62,54%

Na2SO4
mNa2SO4= 2* 23g+32g+4*16g= 142g
46/142*100%=32,4%

Answer 2

AlClз
27u+3*35u=132u
132u---100%
27u----x
x=27*100/132=20,45%

Pb(NO₃)₂
207u+2*14u+6*16u=331u
331u====100%
207u====x
x=207*100/331=62,54%


Na₂SO₄
2*23u+32u+4*16=142u
142u====100%
46u====x
x=46*100/142=32,40%

Answer 3

AlCl3
M AlCl3 = 132u
%Al = M Al / M AlCl3 *100%
%Al = 2700/132 = 20,5 %
Pb(NO3)2
M Pb(NO3)2 = 331u
% Pb = M Pb / M Pb(NO3)2 * 100 %
% Pb = 20700/ 331 = 62,5 %
Na2SO4
M Na2SO4 = 142 u
% Na = M Na / M Na2SO4 * 100%
% Na = 4600/ 142 = 32,4 %