Oblicz zawartość procentową ( procent masowy ) fosforu w kwasie fosforowym(V).
H3PO4
3h= 3*1u = 3u
P= 31 u
4O= 4* 16 = 64u
3+31+64 = 98u
31u/98u= \/
Odp.: 31.6% masy
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H3PO4
3h= 3*1u = 3u
P= 31 u
4O= 4* 16 = 64u
3+31+64 = 98u
31u/98u= \/
Odp.: 31.6% masy