Oblicz zawartość procentową pierwiastków w tlenku sodu.
Masa: 23x2 + 16 = 62
% Na= 46 x 100% / 62 = 74,2 %
% O = 100% - 74,2% = 25,8%
Na2O=2 * 23 + 16 = 46 + 16 = 62Na = 4662 - 100 % 46 - x %x = (46*100%) : 62 = 74,2 % NaO (tlen) = 1662 - 100%16 - x % x = (16*100%) : 62 = 25,8 % O (tlen)
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Masa: 23x2 + 16 = 62
% Na= 46 x 100% / 62 = 74,2 %
% O = 100% - 74,2% = 25,8%
Na2O=2 * 23 + 16 = 46 + 16 = 62
Na = 46
62 - 100 %
46 - x %
x = (46*100%) : 62 = 74,2 % Na
O (tlen) = 16
62 - 100%
16 - x %
x = (16*100%) : 62 = 25,8 % O (tlen)