Odpowiedź:
Kwas pentanowy --> C₅H₁₀O₂
Jego masa : 60 u + 10u + 32u = 102u
%C= 60 ÷ 102 ×100% ≈ 58,82%
%H= 10÷102×100% ≈ 9,8%
%O = 32÷102×100% ≈ 31,37 %
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Odpowiedź:
Kwas pentanowy --> C₅H₁₀O₂
Jego masa : 60 u + 10u + 32u = 102u
%C= 60 ÷ 102 ×100% ≈ 58,82%
%H= 10÷102×100% ≈ 9,8%
%O = 32÷102×100% ≈ 31,37 %