Oblicz zawartość procentową (%masowy) wody w hydratach:
a)CoCl2 * 6H2O
b)CaSO4 * 2H2O
a)CoCl2 * 6H2O
b)CaSO4 * 2H2O
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mCoCl2 * 6H2O=238u
m 8H2O=108u
238g hydratu-----100%
108g H2O----------x%
x=45,4% H2O
b)CaSO4 * 2H2O
mCaSO4 * 2H2O=172u
m 2H2O=36u
172g hydratu-----100%
36g H2O-----------x%
x=20,9% H2O