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1 cząsteczkaa kwasu siarkowego(IV) H2SO3 składa się z 2 at.H /2u/ +
1 at. S /32u/ + 3 at. O /48u/ = razem 82u.
%S = 32u*100% /82u = 39,02%
%O = 48u*100% /82u = 58,54%
%H = 2u*100% /82u = 2,44%
-------------------------------------
..................razem 100,00%
............................................pozdrawiam