Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]log_5100+log_51,25+log_5\sqrt[3]{25} =log_5(100*1,25*\sqrt[3]{25} )=log_5(125*\sqrt[3]{5^2} )=log_5(5^3*5^\frac{2}{3} )=log_55^{3\frac{2}{3}}=3\frac{2}{3}[/tex]
[tex]log_\frac{1}{2} 0,1-log_\frac{1}{2} \frac{3}{5} +log_\frac{1}{2} 48=log_\frac{1}{2} (\frac{1}{10}:\frac{3}{5} *48)=log_\frac{1}{2} (\frac{1}{10} *\frac{5}{3} *48)=log_{2^{-1}}8=-log_22^3=-3[/tex]
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Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]log_5100+log_51,25+log_5\sqrt[3]{25} =log_5(100*1,25*\sqrt[3]{25} )=log_5(125*\sqrt[3]{5^2} )=log_5(5^3*5^\frac{2}{3} )=log_55^{3\frac{2}{3}}=3\frac{2}{3}[/tex]
[tex]log_\frac{1}{2} 0,1-log_\frac{1}{2} \frac{3}{5} +log_\frac{1}{2} 48=log_\frac{1}{2} (\frac{1}{10}:\frac{3}{5} *48)=log_\frac{1}{2} (\frac{1}{10} *\frac{5}{3} *48)=log_{2^{-1}}8=-log_22^3=-3[/tex]