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Na:
2* mNa=2 * 23u= 46u
O:
mO= 16u
stosunek masy:
46:16
lub
12,5:4
mNa2 = 23u x2 = 46u
mO = 16u
stosunek masowy: masa tlenu/masa wodoru = 16u/46u = 8/23