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............. 19%
28% ................... 19-17 = 2
Roztwory (17% i 28% ) należy zmieszać w stosunku masowym 9 : 2
C(%1) m(r1) = IC(%2) – C(%)I
C(%)
C(%2) m(r2) = IC(%2) – C(%)I
17 9I( 28 – 19)I
19
28 2I( 19 – 7)
m(r1) / m(r2) = 9/2