Oblicz, w ilu gramach chlorku sodu zawarte jest:
a) 11,5g sodu
b) 71g chloru.
mNaCl= 58,5ga) 58,5g NaCl --- 23g Na xgNaCl ----- 11,5g Na x= 29,25g NaClb) 58,5g NaCl --- 35,5g ClxgNaCl ----- 71g Cl x= 117g NaClPozdrawiam, kate66 ;)
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mNaCl= 58,5g
a)
58,5g NaCl --- 23g Na
xgNaCl ----- 11,5g Na
x= 29,25g NaCl
b)
58,5g NaCl --- 35,5g Cl
xgNaCl ----- 71g Cl
x= 117g NaCl
Pozdrawiam, kate66 ;)