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M miedzi - 64u
M siarki - 32u
M tlenu - 16u
M wodoru - 1u
M wody - 16u + 2 · 1u = 18u
M 5H₂0 - 18u · 5 = 90u
M CuSO₄ = 64u + 32u + 4·16u
M CuSO₄ =160u
M CuSO₄ · 5H₂0 = 160u + 90u = 250u
250u ------ 100%
90u ------ x
X = 90u · 100% / 250u
X = 9000% / 250
X = 36%