DANE
h = 40 m
g = 10 m/s²
SZUKANE
v = ?
Z zasady zachowania energii:
Ep = Ek
mgh = mv²/2 /:m
v²/2 = 2gh I*2
v² = 2gh = 2·10m/s²·40m = 800 m²/s²
v = √(800m²/s²)
v = √400*2= 20√2 m/s
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h- wysokość
v- predkość
m- masa
DANE
h = 40 m
g = 10 m/s²
SZUKANE
v = ?
Z zasady zachowania energii:
Ep = Ek
mgh = mv²/2 /:m
v²/2 = 2gh I*2
v² = 2gh = 2·10m/s²·40m = 800 m²/s²
v = √(800m²/s²)
v = √400*2= 20√2 m/s