Odpowiedź:
[tex]a_n=a_1q^{n-1}\\a_3=a_1q^2\\\displaystyle \frac{a_3}{a_1} =\frac{a_1q^2}{a_1} =q^{2} =\frac{16}{4} =4\\q^{2} =4/\sqrt{} \\q=2\quad \lor q=-2\qquad \text {ciag rosnacy q=2}\\S_n=a_1\frac{1-q^n}{1-q} \\S_8=4\cdot\frac{1-2^8}{1-2} =4(2^8-1)=4(256-1)=4\cdot255=1020[/tex]
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Odpowiedź:
[tex]a_n=a_1q^{n-1}\\a_3=a_1q^2\\\displaystyle \frac{a_3}{a_1} =\frac{a_1q^2}{a_1} =q^{2} =\frac{16}{4} =4\\q^{2} =4/\sqrt{} \\q=2\quad \lor q=-2\qquad \text {ciag rosnacy q=2}\\S_n=a_1\frac{1-q^n}{1-q} \\S_8=4\cdot\frac{1-2^8}{1-2} =4(2^8-1)=4(256-1)=4\cdot255=1020[/tex]