Oblicz stęzenie jonów wodorowych w roztworach wodnych o nastepujacych wartosciach pH : 1, 2 , 7, 12
jezeli ph = 1 to stezenie jonów wodorowych jest 0,1 mol/dm3 10 do potegi -1
ph = 2 [H+] = 0.01mol/dm3 10 do potegi -2
ph = 7 [H+] = 0,0000001mol/dm3 10 do potegi -7
ph = 12 [H+] = 0.000000000001mol/dm3 10 do potegi - 12
pozdrawiam
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jezeli ph = 1 to stezenie jonów wodorowych jest 0,1 mol/dm3 10 do potegi -1
ph = 2 [H+] = 0.01mol/dm3 10 do potegi -2
ph = 7 [H+] = 0,0000001mol/dm3 10 do potegi -7
ph = 12 [H+] = 0.000000000001mol/dm3 10 do potegi - 12
pozdrawiam