Oblicz stosunek wagowy węgla do wodoru i skład procentowy butanu.
mC4H10=48u+10u=58u
mC : mH = 48 : 10
mC : mH = 24 : 5
%C=(48/58)*100% = 82,76%
%H=(10/58)*100% = 17,24%
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mC4H10=48u+10u=58u
mC : mH = 48 : 10
mC : mH = 24 : 5
%C=(48/58)*100% = 82,76%
%H=(10/58)*100% = 17,24%