oblicz stosunek wagowy i zawartość procentową wodoru w kwasie H3PO4 WAŻNE !!!! ;P Z góry dziękuje ;**
m H3PO4 = 3*1u+1*31u+4*16u = 98u
%H = 3*1u / 98u * 100% = ok. 3%
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
m H3PO4 = 3*1u+1*31u+4*16u = 98u
%H = 3*1u / 98u * 100% = ok. 3%