Oblicz stosunek masy węgla do masy wodoru i do masy tlenu w cząsteczce metanolu
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Masa C = 12u
Masa H = 1u
Masa O = 16u
Masa
C : H : O
stosunek pierwiastków: 12u : 4*1u : 16u
12 : 4 : 16 |po skróceniu na 4
stosunek wynosi = 3 : 1 : 4