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mO = 16u
mCa / mO = 40u /16u
Ca:O = 5/2
Odpowiedz:Stosunek masowy Ca do O w tlenku wapnia wynosi 5:2
O- ≈16
40,078u:16u=2,5
1:2,5
mO=16u
40:16=20:8=10:4=5:2