Oblicz stosunek masowy pierwiastków w bromku wapniaCaBr2 .
tlenku żelaza(III)Fe2O3
tlenku żelaza(III)Fe2O3
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mBr=2*80=160u
stosunek 40:160 1:4
mFe=56*2=112u
mO=16*3=48u
stosunek 112:48 7:3
Ca/2Br = 40/160 = 1:4
tlenek żelaza (III)
Fe2O3 = 2 Fe/3O = 2*56 / 3*16 = 112/48 = 7:3