Oblicz stosunek masowy pierwiastków w: a) grupie aminowej b) metyloaminie
a) NH2
n- 14 u
h - 2 u
N : O = 14 : 2 = 7 :1
b) CH3NH2
C- 12
H- 5
N - 14
C : H : N = 12 : 5 : 14
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a) NH2
n- 14 u
h - 2 u
N : O = 14 : 2 = 7 :1
b) CH3NH2
C- 12
H- 5
N - 14
C : H : N = 12 : 5 : 14