Oblicz stosunek masowy pierwiastków w: a) bromku wapnia CaBr2 b) tlenku żelaza (III) Fe2O3
a) bromek wapnia CaBr2
mCa = 40g
mBr = 2*80g =160g
Ca : Br
40 : 160
4 : 16
1 : 4
b) tlenek żelaza (III) Fe2O3
mFe = 2*56g = 112g
mO = 3*16g = 48g
112 : 48
56 : 24
28 : 12
14 : 6
7 : 3
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a) bromek wapnia CaBr2
mCa = 40g
mBr = 2*80g =160g
Ca : Br
40 : 160
4 : 16
1 : 4
b) tlenek żelaza (III) Fe2O3
mFe = 2*56g = 112g
mO = 3*16g = 48g
112 : 48
56 : 24
28 : 12
14 : 6
7 : 3