a) Bi2O5
mBi = 2 × 209 = 418 u
mO = 5 × 16 = 80 u
stosunek masowy
418 : 80
209 : 40
b) Mn2O7
mMn = 2 × 55 = 110 u
mO = 7 × 16 = 112 u
110 : 112
55 : 56
c) NaCl
mNa = 23 u
mCl = 35 u
23 : 35
d) NH3
mN = 14 u
mH = 3 × 1 = 3 u
14 : 3
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a) Bi2O5
mBi = 2 × 209 = 418 u
mO = 5 × 16 = 80 u
stosunek masowy
418 : 80
209 : 40
b) Mn2O7
mMn = 2 × 55 = 110 u
mO = 7 × 16 = 112 u
stosunek masowy
110 : 112
55 : 56
c) NaCl
mNa = 23 u
mCl = 35 u
stosunek masowy
23 : 35
d) NH3
mN = 14 u
mH = 3 × 1 = 3 u
stosunek masowy
14 : 3