a) mCaS=40u+32u=72 u
mCa:mS=40:32=5:4
40u---x%
72u---100%
x=55,56%Ca
100%-55,56%=44,44%S
b) mAlCl3=27u+3*35,5u=133,5u
mAl:mCl=27:106,5=54:213=18:71
27u---x%
133,5u---100%
x=20,22%Al
100%-20,22%=79,78%Cl
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a) mCaS=40u+32u=72 u
mCa:mS=40:32=5:4
40u---x%
72u---100%
x=55,56%Ca
100%-55,56%=44,44%S
b) mAlCl3=27u+3*35,5u=133,5u
mAl:mCl=27:106,5=54:213=18:71
27u---x%
133,5u---100%
x=20,22%Al
100%-20,22%=79,78%Cl