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stosunek masowy K 2 x 39 = 78, O = 16
stosunek masowy 78 : 16 = 39 : 8
zawartość procentowa %K = 78/94 x 100% = 83%
% O = 17%
Fe2S3 stosunek masowy m Fe = 2x 56 = 112 , m S= 3x32 = 96
Fe:S = 112: 96 = 7:6
zawartość procentowa %Fe= 112/ 208 x 100%= 54%, %S = 46%