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N2O tlenek azotu I
M N2O = 14 * 2 + 16 = 28 + 16 = 44 u
% azotu = 28/44 * 100 % = 63,64 %
stosunek masowy azotu do tlenu
28 : 16
7 : 4
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b) 36,84 %
N2O3 - tlenek azotu III
N2O3 = 14 * 2 + 16 * 3 = 28 + 48 = 76 u
% azotu = 28/76 * 100 % = 36,84 %
stosunek masowy azotu do tlenu
28 : 48
14 : 24
7 : 12