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Al:cl
27:106,5
,FeO=72
Fe:O
56:16
7:2
3mCl=3*35,5=106,5
mAl/3mCl=27u/106u=27/106,5=9/35,5
----
mFe=56u
mO=16u
mFe/mO=56u/16u=56/16=7/2
FeO 1/1 rozwiązanie 2/7