oblicz stosunek mas pierwiastków cząsteczki Na2O, H3PO4, C9H19COOH
Na2O = Na2 / O = 23u * 2 / 16u = 46/16 = 23/8
H3PO4 = H3/ PO4 =1u*3 / 16u*4 +30= 3/94
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Na2O = Na2 / O = 23u * 2 / 16u = 46/16 = 23/8
H3PO4 = H3/ PO4 =1u*3 / 16u*4 +30= 3/94