oblicz stezenie procentowe kwasu solnegootrzymanego w wyniku rozpuszczenia 20g chlorowodoru w 180g wody
do 50g 4%roztworu dodano 10g chlorowodoru.
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1cp=(ms/mr)*100%
cp=20g/200g *100%=100%/10=10%
2.
4%=ms/50g*100%
0,04=ms/50
ms=2g
ms2=2+10=12
mr2=50+10=60
cp=12/60*100%=1/5*100%=100%/5=20%