Oblicz stężenie procentowe wodorotlenku sodu otrzymanego w wyniku rozpuszczenia 5,6 g NaOH w 90 g wody .
ms = 5,6 g
mw = 90g
mr = ms+mw = 90g+,6g = 95,6 g
cp = ms*100%/mr = 5,6g*100%/95,6g = ok. 6%
ms = 5,6g
mr = 5,6g + 90g = 95,6g
cp = 5,86%
W razie pytań pisz
I hope I helped
Pozdrawiam Marco12 :)
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ms = 5,6 g
mw = 90g
mr = ms+mw = 90g+,6g = 95,6 g
cp = ms*100%/mr = 5,6g*100%/95,6g = ok. 6%
ms = 5,6g
mr = 5,6g + 90g = 95,6g
cp = 5,86%
W razie pytań pisz
I hope I helped
Pozdrawiam Marco12 :)