oblicz stężenie procentowe roztworu CuSO4 otrzymanego po rozpuszczeniu 500 g CuSo4 * 5H2O w 500 g wody.
m CuSO₄ x 5H₂O = 64u + 32u + 4 x 16u + 5 x(1 x 2u + 16u) = 250u
m CuSO₄ - 160u
160u x
----- = -----
250u 500g
x = 320g
x = 320g -- tyle mamy soli w hydracie
m H₂O - 500g
ms = 320g
m hydratu - 500g
mr = 1000g
cp = ms/mr x 100%
cp = 320g/1000g x 100% = 32%
Pozdrawiam, Marcin ;)
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m CuSO₄ x 5H₂O = 64u + 32u + 4 x 16u + 5 x(1 x 2u + 16u) = 250u
m CuSO₄ - 160u
160u x
----- = -----
250u 500g
x = 320g
x = 320g -- tyle mamy soli w hydracie
m H₂O - 500g
ms = 320g
m hydratu - 500g
mr = 1000g
cp = ms/mr x 100%
cp = 320g/1000g x 100% = 32%
Pozdrawiam, Marcin ;)