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56g KOH --- 1mol
20g KOH --- xmoli
x = 0,36mola
Z def. stęż. molowego
0,36mola KOH ----- 220cm³ roztworu
xmoli KOH --------- 1000cm³ roztworu
x = 1,64mola
x = 1,64mol/dm³
n=m/M = liczba moli = masa substancji / masa molowa substancji }
1 ml = 1 cm3
M KOH =39+16+1 = 56 g/mol
V r = 200ml = 200cm3 = 0,2 dm3
m KOH = 20g
n=m/M = 20g/56g/mol = 0,36 mol
Cn = 0,36 mol / 0,2 dm3 = 1,8 mol/dm3