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[H⁺] = 10^(-pH)
[OH⁻] = 10^(-pOH)
pOH = -log[OH⁻]
pH + pOH = 14
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0,001M KOH
[OH⁻] = 0,001 mol/dm³
pOH = -log(0,001) = 3
pH + pOH = 14
pH = 14 - pOH
pH = 14-3 = 11
[H⁺] = 10^⁻¹¹ mol/dm³
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0,02M HCl
[H⁺] = 0,02 mol/dm³
pH = -log(0,02) = 1,70
pH + pOH = 14
pOH = 14-pH
pOH = 14 - 1,70 = 12,3
[OH⁻] = 10^(-12,3) = 5,012*10^⁻¹³ mol/dm3
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0,05M NaOH
[OH⁻] = 0,05 mol/dm³
pOH = -log(0,05) = 1,30
pH + pOH = 14
pH = 14-1,3 = 12,7
[H⁺] = 10^(-12,7) = 2,00*10^⁻¹³ mol/dm³
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0,01M HNO₃
[H⁺] = 0,01 mo/dm³
pH = -log(0,01) = 2
pH + pOH = 14
pOH = 14 - 2 = 12
[OH⁻] = 10^⁻¹² mol/dm³
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