Oblicz stałe A i B, wiedząc, że ułamek algebraiczny ...
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[tex]\dfrac{A}{x-1}+\dfrac{B}{x+2}=\dfrac{A(x+2)}{(x-1)(x+2)}+\dfrac{B(x-1)}{(x-1)(x+2)}=\dfrac{Ax+2A+Bx-B}{(x-1)(x+2)}=\\\\=\dfrac{(A+B)x+2A-B}{(x-1)(x+2)}=[/tex]
[tex]A+B=1\\\underline{2A-B=-7}\\3A=-6\\A=-2\\\\-2+B=1\\B=3[/tex]