Oblicz skład procentowy (procent masowy) pierwiastków chemicznych w metanie.
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masa CH4 = 12u + 4u =16u
masa H = 4u
masa C = 12u
%C = 12u/16u * 100% = 75%
%H = 4u/16u * 100% = 25%
masa metanu: 12u + 4 * 1u = 16u
węgiel: 12u
16u ---- 100%
12u ---- x %
x = (12u * 100%) : 16u = 75%
wodór: 4 * 1u = 4u
16u ---- 100%
4u --- x %
x = (4u * 100%) : 16u = 25%