Question

Oblicz skład procentowy pierwiastków w związkach chemicznych? a. tlenek siarki (VI), b. siarczku glinu.

Answer 1

a) mSO3=32u+48u=80u
%S = (32/80)*100 = 40%
%O = (48/80)*100 = 60%

b) mAl2S3=54u+96u=150u
%Al = (54/150)*100% = 36%
%S= (96/150)*100% = 64%

Answer 2

 

a)

m SO₃ = 32u + 3 x 16u = 80u

m S = 32u

m O = 3 x 16u = 48u

 

%S = 32u/80u x 100% = 40%

%O = 48u/80u x 100^ = 60%

 

b)

m Al₂S₃ = 2 x 27u + 3 x 32u = 150u

m Al = 2 x 27u = 54u

m S = 3 x 32u = 96u

 

% Al = 54u/150u x 100% = 36%

% S = 96u/150u x 100% = 64%

 

 

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Pozdrawiam :)