Błędnie podana masa atomowa siarki
mS=32u, mO=16u
mSO3=32u+48u=80u
%S = (32/80)*100% = 40%
%S = (48/80)*100% = 60%
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Błędnie podana masa atomowa siarki
mS=32u, mO=16u
mSO3=32u+48u=80u
%S = (32/80)*100% = 40%
%S = (48/80)*100% = 60%