Oblicz skład procentowy pierwiastków w nastepujacych zwiazkach chemicznych.
Tlenku siarki(VI)
siarczku glinu
Tlenku siarki(VI) SO2
M SO2 = 32u + 2*16u = 32u + 32u = 64u
% O = 32u/64u * 100% = 50%
% S = 32u/64u * 100% = 50%
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siarczku glinu Al2S3
M Al2S3 = 2*27 u + 3*32u = 54u + 96u = 150u
% Al = 54u/150u * 100% = 36%
% S = 96u/150u * 100% = 64 %
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SO3
32u + 3* 16u = 80u
80u - 100%
32u - x
x=3200:80
x=40% - siarka
tlen 100%-40%=60%
Siarczek glinu
Al2S3
2*27u+3*32u=54u+96u=150u
150u - 100%
54u - x
x=5400:150
x= 36% glin
100%-36%=64% - siarka
Tlenku siarki(VI) SO2
M SO2 = 32u + 2*16u = 32u + 32u = 64u
% O = 32u/64u * 100% = 50%
% S = 32u/64u * 100% = 50%
_________________________________________
siarczku glinu Al2S3
M Al2S3 = 2*27 u + 3*32u = 54u + 96u = 150u
% Al = 54u/150u * 100% = 36%
% S = 96u/150u * 100% = 64 %