Oblicz skład procentowy pierwiastków w kwasie heptynowym i stosunek masowy węgla do tlenu i wodoru w tym związku.
CH≡C-CH2-CH2-CH2-CH2-COOH = C7H10O2
mC7H10O2=84u+10u+32u=126u
%C = (84/126)*100% = 66,7% C
%H = (10/126)*100% = 7,9% H
%O = (32/126)*100% = 25,4% O
mC : mH : mO = 84 : 10 : 32
mC : mH : mO = 42 : 5 : 16
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CH≡C-CH2-CH2-CH2-CH2-COOH = C7H10O2
mC7H10O2=84u+10u+32u=126u
%C = (84/126)*100% = 66,7% C
%H = (10/126)*100% = 7,9% H
%O = (32/126)*100% = 25,4% O
mC : mH : mO = 84 : 10 : 32
mC : mH : mO = 42 : 5 : 16