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z1 i z2 to objetosci wodoru
x z1
2ch3oh+2Na=2ch3oNa+ h2
64g 22,4dm3
3,76-x z2
2c2h5oh+2Na=2c2h5oNa+h2
92 22,4dm3
z1=22,4x/64=0,35x
z2=0,92-0,24x
z1+z2=0,92+0,11x
1,12=0,92+0,11x
0,2=0,11x
x=1,82g metanolu
3,76-1,82=1,94g etanolu
:)