oblicz skład % mrówczanu etylu
prosze pilne bardzo !!!
HCOOCH2CH3 to jest wzór
masa: (12u x 3) + (16u x 2) + (1u x 6)=74u
C: 36/74 x 100%=48,6%
H: 6/74 x 100%=8,1%
O: 32/74 x 100%=43,2%
mHCOOC2H5=6*1u+2*16u+3*12u=6u+32u+36u=74u
%H=6u/74u * 100%
%H=8,1%
%O=32u/74u * 100%
%O=43,2%
%C=36u/74u * 100%
%C=48,7%
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HCOOCH2CH3 to jest wzór
masa: (12u x 3) + (16u x 2) + (1u x 6)=74u
C: 36/74 x 100%=48,6%
H: 6/74 x 100%=8,1%
O: 32/74 x 100%=43,2%
mHCOOC2H5=6*1u+2*16u+3*12u=6u+32u+36u=74u
%H=6u/74u * 100%
%H=8,1%
%O=32u/74u * 100%
%O=43,2%
%C=36u/74u * 100%
%C=48,7%