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R2=2Ω
R3=3Ω
Rz=?
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R1 i R2 połączone szeregowo
Rz1=R1+R2=1Ω+2Ω=3Ω
Rz1 połączone równolegle z R3
1/Rz=1/Rz1+1/R3
1/Rz=1/3+1/3
1/Rz=2/3
Rz=3/2=1,5Ω
1/Rz = ⅓Ω+⅓Ω = ⅔Ω
Rz= 1½Ω
opór zastepczy to 1½Ω
R1,2=2+1 [OM]
R1,2=3[OM]
/-PRZEZ
1/R=1/R1,2+1/R3 [1/OM]
1/R=1/3+1/3 [1/OM] I TERAZ ZAMINIAM STRONAMI :
CZYLI
R=3+3 [OM]
R=6 OM