A1=79
A2=81
X1=51%
X2=49%
m at.=?
Korzystam ze wzoru na średnią masę atomową
m at. = A1*X1% + A2*X2% /100%
m at. = 79*51% + 81*49%/100%
m at. = 4029+3969/100
m at. = 7998/100
m at. = 79,98u
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A1=79
A2=81
X1=51%
X2=49%
m at.=?
Korzystam ze wzoru na średnią masę atomową
m at. = A1*X1% + A2*X2% /100%
m at. = 79*51% + 81*49%/100%
m at. = 4029+3969/100
m at. = 7998/100
m at. = 79,98u