oblicz przyspieszenie ,z jakim porusza sie klocek o masie 2kg w wyniku dzialania sil f1=15n f2=20n pomozcie:)
F=maa=F/m
F1=15N F2=20N
a1=15N/2kg=7,5 m/s^2a2=20N/2kg=10 m/s^2
m=2kg
F1=15N
F2=20N
a1=F/m
a1=15N/2kg
a1=15N[kg*m/s kwadrat]/2kg
a1=15m/s kwadrat/2
a1=7,5m/s kwadrat
a2=F/m
a2=20N/2kg
a2=10m/s kwadrat
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F=ma
a=F/m
F1=15N F2=20N
a1=15N/2kg=7,5 m/s^2
a2=20N/2kg=10 m/s^2
m=2kg
F1=15N
F2=20N
a1=F/m
a1=15N/2kg
a1=15N[kg*m/s kwadrat]/2kg
a1=15m/s kwadrat/2
a1=7,5m/s kwadrat
a2=F/m
a2=20N/2kg
a2=10m/s kwadrat