Oblicz przyspieszene jakie sila F=20N nada klockowi o masie 5kg.
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F = 20 N
m = 5 kg
szukane:
a = ?
Z II zasady dynamiki Newtona:
F=20N
m=5kg
a=?
F=m*a l:m
a=F/m
a=20N/5kg=(20kg*m/s^2)/5kg= 4m/s^2