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m wegla = 12 x 6 = 72
m wodoru = 14
m substacji = 72+14=86
72/86 x 100% = 83,72%
Procentowa zawartość węgla w heksanie wynosi 83,72%
mC6H14=6*12u+14*1u=86 u
72u-x%
86u-100%
x=83,72%C