Oblicz procentową zawartość pierwiastków w fosforanie V magnezu II
P2Mg5=2*31+5*24=62+120=182
62=x% 100%-34,1%=65,9%
182=100%
x= 62*100/182
x= 34,1%
P to około 34,1%, a Mg to około 65,9%
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P2Mg5=2*31+5*24=62+120=182
62=x% 100%-34,1%=65,9%
182=100%
x= 62*100/182
x= 34,1%
P to około 34,1%, a Mg to około 65,9%