m Na₂SO₄ = 2*23u + 32u + 4*16u = 46u + 32u + 64u = 142u 142u = 100% 46u = x %Na = 4600/142 = 32,4%
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m Na₂SO₄ = 2*23u + 32u + 4*16u = 46u + 32u + 64u = 142u
142u = 100%
46u = x
%Na = 4600/142 = 32,4%
S - 32u
O4 - 4*16u = 64u
46 + 32+64= 142u
142 - 100%
46 - x
x = (46*100) : 142
x = 32,39%