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32g -100%
12-x
x=37,5% C
32-100
16-x
x=50% tlenu
% H =100-50-35,7=12,5%
mC/mCH3OH *100%=12u/32u*100%=37,5%
4mH/mCH3OH *100%=4u/32u*100%=12,5%
mO/mCH3OH *100%=16u/32u*100%=50%