oblicz procent masowy pierwiastków chemicznych w propanolu.
mC3H7OH=3*12u+8*1u+16u=60u
%C=36u/60u * 100%
%C=60%
%H=8u/60u * 100%
%H=13,3%
%O=16u/60u * 100%
%O=26,7%
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mC3H7OH=3*12u+8*1u+16u=60u
%C=36u/60u * 100%
%C=60%
%H=8u/60u * 100%
%H=13,3%
%O=16u/60u * 100%
%O=26,7%